Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - 7.3 Logarithms and Their Derivatives - Exercises - Page 343: 96


$\frac{1}{8}(4\ln x+5)^2+c.$

Work Step by Step

Let $ u=4\ln x+5$, then $ du= \frac{4}{x} dx $ and hence $$\int \frac{4\ln x +5}{x}dx = \frac{1}{4}\int udu=\frac{1}{8}u^2+c\\ =\frac{1}{8}(4\ln x+5)^2+c.$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.