Answer
$\ln 3. $
Work Step by Step
Using the fact that $\frac{u'}{u}=\ln u $, we have
$$\int_4^{12} \frac{1}{x}dx =\ln x|_4^{12}=\ln 12-\ln 4=\ln \frac{12}{4}=\ln 3. $$
where used the property $\ln A-\ln B=\ln \frac{A}{B}.$
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