Answer
$$ y'=7^{4x-x^2} (4-2x) \ln 7.$$
Work Step by Step
Recall that the derivative of $ a^{f(x)}$ is $ a^{f(x)} f'(x)\ln a $
Since $ y=7^{4x-x^2}$, we have
$$ y'=7^{4x-x^2} (4-2x) \ln 7.$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.3 Logarithms and Their Derivatives - Exercises - Page 343: 46
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