Answer
$h''(t)=-10\cos{t}+15\sin{t}.$
Work Step by Step
$h'(t)=\dfrac{d}{dt}(10\cos{t})-\dfrac{d}{dt}(15\sin{t})=-10\sin{t}-15\cos{t}.$
$h''(t)=\dfrac{d}{dt}(-10\sin{t})+\dfrac{d}{dt}(-15\cos{t})=-10\cos{t}+15\sin{t}.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - Review Exercises - Page 157: 50
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
