Answer
The slope of the tangent at the point $(0, -8)$ is $0.$
Work Step by Step
$f'(x)=\dfrac{d}{dx}(2x^4)-\dfrac{d}{dx}(8)=8x^3.$
$f'(0)=8(0^3)=0.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - Review Exercises - Page 157: 23
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