Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - Review Exercises - Page 157: 24

Answer

The slope of the tangent at the point $(0, 3)$ is $-2.$

Work Step by Step

$f'(\theta)=\dfrac{d}{d\theta}(3\cos{\theta})-\dfrac{d}{d\theta}(2\theta)=-3\sin{\theta}-2.$ $f'(0)=-3\sin{0}-2=-2.$
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