Answer
The slope of the tangent at the point $(1, -1)$ is $2.$
Work Step by Step
$f'(x)=\dfrac{d}{dx}(3x^2)-\dfrac{d}{dx}(4x)=6x-4.$
$f'(1)=6(1)-4=2.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - Review Exercises - Page 157: 22
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