Answer
$f'(\theta)=-3\sin{\theta}-\dfrac{\cos{\theta}}{4}$.
Work Step by Step
$f'(\theta)=\dfrac{d}{d\theta}(3\cos{\theta})-\dfrac{d}{d\theta}(\dfrac{\sin{\theta}}{4})\rightarrow$
$f'(\theta)=-3\sin{\theta}-\dfrac{\cos{\theta}}{4}$.
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - Review Exercises - Page 157: 19
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