Answer
$f'(x)=20x^3-60x^2-44x-32.$
Work Step by Step
Product Rule $(f’(x)=(u(x)(v(x))’=u’(x)v(x)+u(x)v’(x))$
$u(x)=5x^2+8 ;u’(x)=10x $
$v(x)=x^2-4x-6 ;v’(x)= 2x-4$
$f'(x)=(10x)(x^2-4x-6)+(2x-4)(5x^2+8)$
$=20x^3-60x^2-44x-32.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - Review Exercises - Page 157: 29
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