Answer
$g'(\alpha)=-4\sin{\alpha}.$
Work Step by Step
$g'(\alpha)=\dfrac{d}{d\alpha}(4\cos{\alpha})+\dfrac{d}{d\alpha}(6)\rightarrow$
$g'(\alpha)=-4\sin{\alpha}.$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.