Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 9 - Section 9.1 - Solving Quadratic Equations by the Square Root Property - Exercise Set - Page 631: 44


$c=\sqrt{146} \text{ } in$

Work Step by Step

Using $a^2+b^2=c^2$ or the Pythagorean Theorem, then, \begin{array}{l}\require{cancel} 5^2+11^2=c^2 \\\\ 25+121=c^2 \\\\ 146=c^2 \\\\ c=\pm\sqrt{146} .\end{array} Since there are no negative measurements, then $ c=\sqrt{146} \text{ } in .$
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