Answer
$x=\{−1 \pm \sqrt 5\}$
Work Step by Step
The left side of the given equation, $x^2+2x+1=5$, is a perfect square trinomial whose factored form is
$(x+1)^2=5$.
Taking the square root of both sides (the Square Root Property), the solutions to the given equation are
$x+1=\pm\sqrt {5}$
$x=−1+\sqrt 5$ or $x=-1-\sqrt 5$
Hence, $x=\{−1 \pm \sqrt 5\}$.
