Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 9 - Section 9.1 - Solving Quadratic Equations by the Square Root Property - Exercise Set - Page 631: 35


$x=\{−1 \pm \sqrt 5\}$

Work Step by Step

The left side of the given equation, $x^2+2x+1=5$, is a perfect square trinomial whose factored form is $(x+1)^2=5$. Taking the square root of both sides (the Square Root Property), the solutions to the given equation are $x+1=\pm\sqrt {5}$ $x=−1+\sqrt 5$ or $x=-1-\sqrt 5$ Hence, $x=\{−1 \pm \sqrt 5\}$.
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