# Chapter 9 - Section 9.1 - Solving Quadratic Equations by the Square Root Property - Exercise Set - Page 631: 26

$x=\left\{ 3-\sqrt{15},3+\sqrt{15} \right\}$

#### Work Step by Step

Taking the square root of both sides (the Square Root Property), the solutions to the given equation, $(x-3)^2=15 ,$ are \begin{array}{l}\require{cancel} x-3=\pm\sqrt{15} \\\\ x=3\pm\sqrt{15} .\end{array} Hence, $x=\left\{ 3-\sqrt{15},3+\sqrt{15} \right\} .$

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