## Introductory Algebra for College Students (7th Edition)

$x=\left\{ -\dfrac{5}{3},\dfrac{1}{3} \right\}$
Taking the square root of both sides (the Square Root Property), the solutions to the given equation, $(3x+2)^2=9 ,$ are \begin{array}{l}\require{cancel} (3x+2)=\pm\sqrt{9} \\\\ 3x+2=\pm\sqrt{(3)^2} \\\\ 3x+2=\pm3 \\\\ 3x=-2\pm3 \\\\ x=\dfrac{-2\pm3}{3} .\end{array} Hence, $x=\left\{ -\dfrac{5}{3},\dfrac{1}{3} \right\} .$