Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 9 - Section 9.1 - Solving Quadratic Equations by the Square Root Property - Exercise Set: 22

Answer

$x=\{ -18,6 \}$

Work Step by Step

Taking the square root of both sides (the Square Root Property), the solutions to the given equation, $ (x+6)^2=144 ,$ are \begin{array}{l}\require{cancel} (x+6)=\pm\sqrt{144} \\\\ x+6=\pm\sqrt{(12)^2} \\\\ x+6=\pm12 \\\\ x=-6\pm12 .\end{array} Hence, $ x=\{ -18,6 \} .$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.