Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 9 - Section 9.1 - Solving Quadratic Equations by the Square Root Property - Exercise Set - Page 631: 17



Work Step by Step

Using the properties of equality, the given equation, $ 5x^2-7=0 ,$ is equivalent to \begin{array}{l}\require{cancel} 5x^2=7 \\\\ x^2=\dfrac{7}{5} .\end{array} Taking the square root of both sides (the Square Root Property), the solutions to the given equation are \begin{array}{l}\require{cancel} x=\pm\sqrt{\dfrac{7}{5}} \\\\ x=\pm\sqrt{\dfrac{7}{5}\cdot\dfrac{5}{5}} \\\\ x=\pm\sqrt{\dfrac{35}{25}} \\\\ x=\pm\dfrac{\sqrt{35}}{\sqrt{25}} \\\\ x=\pm\dfrac{\sqrt{35}}{\sqrt{(5)^2}} \\\\ x=\pm\dfrac{\sqrt{35}}{5} .\end{array}
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