## Introductory Algebra for College Students (7th Edition)

$x=\pm\dfrac{\sqrt{35}}{5}$
Using the properties of equality, the given equation, $5x^2-7=0 ,$ is equivalent to \begin{array}{l}\require{cancel} 5x^2=7 \\\\ x^2=\dfrac{7}{5} .\end{array} Taking the square root of both sides (the Square Root Property), the solutions to the given equation are \begin{array}{l}\require{cancel} x=\pm\sqrt{\dfrac{7}{5}} \\\\ x=\pm\sqrt{\dfrac{7}{5}\cdot\dfrac{5}{5}} \\\\ x=\pm\sqrt{\dfrac{35}{25}} \\\\ x=\pm\dfrac{\sqrt{35}}{\sqrt{25}} \\\\ x=\pm\dfrac{\sqrt{35}}{\sqrt{(5)^2}} \\\\ x=\pm\dfrac{\sqrt{35}}{5} .\end{array}