Answer
$x=\pm\dfrac{\sqrt{15}}{3}$
Work Step by Step
Using the properties of equality, the given equation, $
3x^2-5=0
,$ is equivalent to
\begin{array}{l}\require{cancel}
3x^2=5
\\\\
x^2=\dfrac{5}{3}
.\end{array}
Taking the square root of both sides (the Square Root Property), the solutions to the given equation are
\begin{array}{l}\require{cancel}
x=\pm\sqrt{\dfrac{5}{3}}
\\\\
x=\pm\sqrt{\dfrac{5}{3}\cdot\dfrac{3}{3}}
\\\\
x=\pm\sqrt{\dfrac{15}{9}}
\\\\
x=\pm\dfrac{\sqrt{15}}{\sqrt{9}}
\\\\
x=\pm\dfrac{\sqrt{15}}{\sqrt{(3)^2}}
\\\\
x=\pm\dfrac{\sqrt{15}}{3}
.\end{array}
