Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 9 - Section 9.1 - Solving Quadratic Equations by the Square Root Property - Exercise Set: 24

Answer

$x=\left\{ -4,3 \right\}$

Work Step by Step

Taking the square root of both sides (the Square Root Property), the solutions to the given equation, $ (2x+1)^2=49 ,$ are \begin{array}{l}\require{cancel} (2x+1)=\pm\sqrt{49} \\\\ 2x+1=\pm\sqrt{(7)^2} \\\\ 2x+1=\pm7 \\\\ 2x=-1\pm7 \\\\ x=\dfrac{-1\pm7}{2} .\end{array} Hence, $ x=\left\{ -4,3 \right\} .$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.