Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Section 8.3 - Operations with Radicals - Exercise Set - Page 591: 43


$\sqrt{6} + \sqrt{10}$

Work Step by Step

RECALL: (i) For non-negative real numbers $a$ and $b$, $\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}$ (ii) For all real numbers $a, b,$ and $c$, $a(b+c) = ab+ac$ Use rule (ii) above to obtain: $=\sqrt{2} \cdot \sqrt{3} +\sqrt{2} \cdot \sqrt{5}$ Use rule (i) above to obtain: $=\sqrt{6} + \sqrt{10}$
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