Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Section 8.3 - Operations with Radicals - Exercise Set: 36

Answer

$3\sqrt{2}+8$

Work Step by Step

Simplify the radicals that can still be simplified by factoring the radicand so that one of the factors is a perfect square: $=\sqrt{6}+\sqrt{3^2}+\sqrt{4(6)}+\sqrt{5^2} \\=\sqrt{6}+3+\sqrt{2^2(6)}+5 \\=\sqrt{6}+3+2\sqrt{6}+5$ RECALL: For any real numbers $, a, b,$ and $c$, $ac+bc=(a+b)c$ Use the rule above to combine like terms: $=(\sqrt{6}+2\sqrt{6}) + 3+5 \\=(1+2)\sqrt{2}+8 \\=3\sqrt{2}+8$
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