Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Section 8.3 - Operations with Radicals - Exercise Set - Page 591: 39



Work Step by Step

Factor the radicands so that one of the factors is a perfect square: $=2\sqrt{16(5)}+3\sqrt{25(3)} \\=2\sqrt{4^2(5)} +3\sqrt{5^2(3)}$ Simplify to obtain: $\\=2\cdot 4\sqrt{5}+3\cdot 5\sqrt{3} \\=8\sqrt{5}+15\sqrt{3}$
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