# Chapter 8 - Section 8.3 - Operations with Radicals - Exercise Set: 38

$\sqrt{3} + \sqrt{13}$ (cannot be simplified further)

#### Work Step by Step

A radical involving a square is already in lowest terms when the radicand has no perfect square factor. Note that the radicands of $\sqrt{3}$ and $\sqrt{13}$ are prime numbers, which means that they have no factors other than themselves. Therefore, the given expression is already in lowest terms.

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