Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Section 8.3 - Operations with Radicals - Exercise Set - Page 591: 31

Answer

$9\sqrt{3}-6\sqrt{2}$

Work Step by Step

Simplify the radicals that can still be simplified by factoring the radicand so that one of the factors is a perfect square: $=3\sqrt{9(3)}-2\sqrt{9(2)} \\=3\sqrt{3^2(3)} -2\sqrt{3^2(2)} \\=3\cdot 3\sqrt{3} -2\cdot 3\sqrt{2} \\=9\sqrt{3}-6\sqrt{2}$
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