Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Section 8.3 - Operations with Radicals - Exercise Set: 29

Answer

$19\sqrt{3}$

Work Step by Step

Simplify the radicals that can still be simplified by factoring the radicand so that one of the factors is a perfect square: $=7\sqrt{4(3)}+\sqrt{25(3)} \\=7\sqrt{2^2(3)} +\sqrt{5^2(3)} \\=7\cdot 2\sqrt{3} + 5\sqrt{3} \\=14\sqrt{3}+5\sqrt{3}$ RECALL: For any real numbers $a, b,$ and $c$, $ac+bc=(a+b)c$ Use the rule above to combine like terms: $=(14+5)\sqrt{3} \\=19\sqrt{3}$
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