## Introductory Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 8 - Section 8.3 - Operations with Radicals - Exercise Set - Page 591: 30

#### Answer

$15\sqrt{3}$

#### Work Step by Step

Simplify the radicals that can still be simplified by factoring the radicand so that one of the factors is a perfect square: $=5\sqrt{4(3)}+\sqrt{25(3)} \\=5\sqrt{2^2(3)} +\sqrt{5^2(3)} \\=5\cdot 2\sqrt{3} + 5\sqrt{3} \\=10\sqrt{3}+5\sqrt{3}$ RECALL: For any real numbers $a, b,$ and $c$, $ac+bc=(a+b)c$ Use the rule above to combine like terms: $=(10+5)\sqrt{3} \\=15\sqrt{3}$

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