Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Section 8.3 - Operations with Radicals - Exercise Set: 34

Answer

$4\sqrt{2x}$

Work Step by Step

Simplify the radicals that can still be simplified by factoring the radicand so that one of the factors is a perfect square: $=2\sqrt{25(2x)}-2\sqrt{9(2x)} \\=2\sqrt{5^2(2x)} -2\sqrt{3^2(2x)} \\=2\cdot 5\sqrt{2x} -2\cdot 3\sqrt{2x} \\=10\sqrt{2x}-6\sqrt{2x}$ RECALL: For any real numbers $, a, b,$ and $c$, $ac+bc=(a+b)c$ Use the rule above to combine like terms: $=(10-6)\sqrt{2x} \\=4\sqrt{2x}$
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