## Introductory Algebra for College Students (7th Edition)

$2\sqrt[4]{2}$
Getting the perfect factors and then extracting its root, the simplified form of the given expression, $\sqrt[4]{32} ,$ is \begin{array}{l}\require{cancel} \sqrt[4]{16\cdot2} \\\\= \sqrt[4]{(2)^4\cdot2} \\\\= 2\sqrt[4]{2} .\end{array}