## Introductory Algebra for College Students (7th Edition)

$\sqrt{14}$
Using $\sqrt{x}\cdot\sqrt{y}=\sqrt{xy}$ or the product rule of radicals, the given expression, $\sqrt{2}\cdot\sqrt{7} ,$ is equivalent to \begin{array}{l}\require{cancel} \sqrt{2(7)} \\\\= \sqrt{14} .\end{array}