## Introductory Algebra for College Students (7th Edition)

$2x\sqrt{2}$
Getting the perfect factors and then extracting its root, the simplified form of the given expression, $\sqrt{8x^2} ,$ is \begin{array}{l}\require{cancel} \sqrt{4x^2\cdot2} \\\\= \sqrt{(2x)^2\cdot2} \\\\= 2x\sqrt{2} .\end{array}