Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Section 8.2 - Multiplying and Dividing Radicals - Exercise Set - Page 585: 40



Work Step by Step

Getting the perfect factors and then extracting its root, the simplified form of the given expression, $ \sqrt{24x^{8}} ,$ is \begin{array}{l}\require{cancel} \sqrt{4x^8\cdot6} \\\\= \sqrt{(2x^4)^2\cdot6} \\\\= 2x^4\sqrt{6} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.