Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Section 8.2 - Multiplying and Dividing Radicals - Exercise Set - Page 585: 89



Work Step by Step

Using $\sqrt{\dfrac{x}{y}}=\dfrac{\sqrt{x}}{\sqrt{y}}$ or the quotient rule of radicals, the given expression, $ \dfrac{\sqrt{150x^4}}{\sqrt{3x}} ,$ simplifies to \begin{array}{l}\require{cancel} \sqrt{\dfrac{150x^4}{3x}} \\\\= \sqrt{\dfrac{50x^3\cdot\cancel{3x}}{\cancel{3x}}} \\\\= \sqrt{50x^3} \\\\= \sqrt{25x^2\cdot2x} \\\\= \sqrt{(5x)^2\cdot2x} \\\\= 5x\sqrt{2x} .\end{array} Note that variables are assumed to have positive real numbers.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.