Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Section 8.2 - Multiplying and Dividing Radicals - Exercise Set - Page 585: 46



Work Step by Step

Getting the perfect factors and then extracting its root, the simplified form of the given expression, $ \sqrt{x^9} ,$ is \begin{array}{l}\require{cancel} \sqrt{x^8\cdot x} \\\\= \sqrt{(x^4)^2\cdot x} \\\\= x^4\sqrt{x} .\end{array} Note that variables are assumed to represent positive real numbers.
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