Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 8 - Section 8.2 - Multiplying and Dividing Radicals - Exercise Set - Page 585: 12

Answer

$\dfrac{1}{7}\sqrt{ab}$

Work Step by Step

Using $\sqrt{x}\cdot\sqrt{y}=\sqrt{xy}$ or the product rule of radicals, the given expression, $ \sqrt{\dfrac{1}{7}a}\cdot\sqrt{\dfrac{1}{7}b} ,$ is equivalent to \begin{array}{l}\require{cancel} \sqrt{\dfrac{1}{7}a\cdot\dfrac{1}{7}b} \\\\= \sqrt{\left(\dfrac{1}{7}\right)^2ab} \\\\= \dfrac{1}{7}\sqrt{ab} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.