## Introductory Algebra for College Students (7th Edition)

$y^8\sqrt{y}$
Getting the perfect factors and then extracting its root, the simplified form of the given expression, $\sqrt{y^{17}} ,$ is \begin{array}{l}\require{cancel} \sqrt{y^{16}\cdot y} \\\\= \sqrt{(y^8)^2\cdot y} \\\\= y^8\sqrt{y} .\end{array} Note that variables are assumed to represent positive real numbers.