Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.7 - Negative Exponents and Scientific Notation - Exercise Set - Page 409: 76

Answer

$\dfrac{8}{x^{6}}$

Work Step by Step

Using the laws of exponents, the given expression, $ \left( \dfrac{x^2}{2} \right)^{-3} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{x^{2(-3)}}{2^{-3}} \\\\= \dfrac{x^{-6}}{2^{-3}} \\\\= \dfrac{2^{3}}{x^{6}} \\\\= \dfrac{8}{x^{6}} .\end{array}
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