Answer
$64y^{19}$
Work Step by Step
Using the laws of exponents, the given expression, $
\dfrac{(4y^5)^3}{y^{-4}}
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{4^{1(3)}y^{5(3)}}{y^{-4}}
\\\\=
\dfrac{4^{3}y^{15}}{y^{-4}}
\\\\=
64y^{15-(-4)}
\\\\=
64y^{15+4}
\\\\=
64y^{19}
.\end{array}