Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.7 - Negative Exponents and Scientific Notation - Exercise Set - Page 409: 49



Work Step by Step

Using the laws of exponents, the given expression, $ \dfrac{(4x^3)^2}{x^8} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{4^{1(2)}x^{3(2)}}{x^8} \\\\= \dfrac{4^{2}x^{6}}{x^8} \\\\= 16x^{6-8} \\\\= 16x^{-2} \\\\= \dfrac{16}{x^2} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.