Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.7 - Negative Exponents and Scientific Notation - Exercise Set: 72

Answer

$\dfrac{1}{a^{20}b^{12}}$

Work Step by Step

Using the laws of exponents, the given expression, $ (a^5b^3)^{-4} ,$ simplifies to \begin{array}{l}\require{cancel} a^{5(-4)}b^{3(-4)} \\\\= a^{-20}b^{-12} \\\\= \dfrac{1}{a^{20}b^{12}} .\end{array}
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