Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.7 - Negative Exponents and Scientific Notation - Exercise Set: 74

Answer

$\dfrac{a^{35}}{b^{10}}$

Work Step by Step

Using the laws of exponents, the given expression, $ (a^{-7}b^2)^{-5} ,$ simplifies to \begin{array}{l}\require{cancel} a^{-7(-5)}b^{2(-5)} \\\\= a^{35}b^{-10} \\\\= \dfrac{a^{35}}{b^{10}} .\end{array}
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