## Introductory Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 5 - Section 5.7 - Negative Exponents and Scientific Notation - Exercise Set - Page 409: 46

#### Answer

$\dfrac{1}{x}$

#### Work Step by Step

Using the laws of exponents, the given expression, $\dfrac{x^5}{(x^3)^2} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{x^5}{x^{3(2)}} \\\\= \dfrac{x^5}{x^{6}} \\\\= x^{5-6} \\\\= x^{-1} \\\\= \dfrac{1}{x^1} \\\\= \dfrac{1}{x} .\end{array}

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