Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.7 - Negative Exponents and Scientific Notation - Exercise Set - Page 409: 67

Answer

$\dfrac{1}{y^2}$

Work Step by Step

Using the laws of exponents, the given expression, $ \dfrac{(y^3)^4}{(y^2)^7} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{y^{3(4)}}{y^{2(7)}} \\\\= \dfrac{y^{12}}{y^{14}} \\\\= y^{12-14} \\\\= y^{-2} \\\\= \dfrac{1}{y^2} .\end{array}
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