Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.7 - Negative Exponents and Scientific Notation - Exercise Set: 61

Answer

$\dfrac{2x^{6}}{5}$

Work Step by Step

Using the laws of exponents, the given expression, $ \dfrac{2x^5\cdot3x^7}{15x^6} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{2(3)x^{5+7-6}}{15} \\\\= \dfrac{2(\cancel{3})x^{5+7-6}}{\cancel{3}(5)} \\\\= \dfrac{2x^{6}}{5} .\end{array}
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