Answer
$x^2-2x-2=0$
Work Step by Step
As we are given that the roots of a quadratic equation as :
{$x-1-\sqrt 3,x-1+\sqrt 3$}
Let us find a quadratic equation for the given roots:
$(x-1-\sqrt 3)(x-1+\sqrt 3)=0$
This implies that after simplifications, we have
$(x-1-\sqrt 3)(x-1+\sqrt 3)=0$
or, $(x-1)^2-(\sqrt 3)^2=0$
or, $x^2-2x+1-3=0$
Thus, $x^2-2x-2=0$
