Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.2 - The Quadratic Formula - Exercise Set - Page 608: 31



Work Step by Step

Re-write the given equation as: $3x^2-4x-4=0$ Factorize the expression as: $3x^2-6x+2x-4=0$ This implies that $(3x+2)(x-2)=0$ Need to apply zero-product property. Thus, $x=\dfrac{-2}{3},2$ Hence, our solution set is: {$\dfrac{-2}{3},2$}
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