## Intermediate Algebra for College Students (7th Edition)

{$\dfrac{-2}{3},2$}
Re-write the given equation as: $3x^2-4x-4=0$ Factorize the expression as: $3x^2-6x+2x-4=0$ This implies that $(3x+2)(x-2)=0$ Need to apply zero-product property. Thus, $x=\dfrac{-2}{3},2$ Hence, our solution set is: {$\dfrac{-2}{3},2$}