Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.2 - The Quadratic Formula - Exercise Set - Page 608: 51

Answer

$x^2-2x-15=0$

Work Step by Step

As we are given that solution set : {$-3,5$} This implies that $x=-3,5$ As per zero-product reverse property, we have $(x+3)(x-5)=0$ Now, apply FOIL METHOD $(x+3)(x-5)=0 \implies x^2-5x+3x-15=0$ or, $x^2-2x-15=0$
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