Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 8 - Section 8.2 - The Quadratic Formula - Exercise Set - Page 608: 37


{$\dfrac{3 - \sqrt {65}}{4},\dfrac{3 + \sqrt {65}}{4}$}

Work Step by Step

Given: $(2x-5)(x+1)=0$ Re-write the given equation as: $2x^2-3x-7=0$ Factorize the expression with the help of quadratic formula. Quadratic formula suggests that $x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$ This implies that $x=\dfrac{-(-3) \pm \sqrt{(-3)^2-4(2)(-7)}}{2(2)}$ or, $x=\dfrac{3 \pm \sqrt {65}}{4}$ or, $x=\dfrac{3 - \sqrt {65}}{4},\dfrac{3 + \sqrt {65}}{4}$ Hence, our solution set is: {$\dfrac{3 - \sqrt {65}}{4},\dfrac{3 + \sqrt {65}}{4}$}
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