# Chapter 8 - Section 8.2 - The Quadratic Formula - Exercise Set - Page 608: 36

{$\dfrac{-6 -2i \sqrt {5}}{4},\dfrac{-6 + 2i \sqrt {5}}{4}$}

#### Work Step by Step

Re-write the given equation as: $2x^2+6x+7=0$ Factorize the expression with the help of quadratic formula. Quadratic formula suggests that $x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$ This implies that $x=\dfrac{-(6) \pm \sqrt{(6)^2-4(2)(7)}}{2(2)}$ or, $x=\dfrac{-6 \pm \sqrt {-20}}{4}$ or, $x=\dfrac{-6 \pm 2i \sqrt {5}}{4}$ or, $x=\dfrac{-6 -2i \sqrt {5}}{4},\dfrac{-6 + 2i \sqrt {5}}{4}$ Hence, our solution set is: {$\dfrac{-6 -2i \sqrt {5}}{4},\dfrac{-6 + 2i \sqrt {5}}{4}$}

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