Answer
$18x^2+9x-5=0$
Work Step by Step
As we are given that solution set : {$-\dfrac{5}{6},\dfrac{1}{3}$}
This implies that $x=-\dfrac{5}{6},\dfrac{1}{3}$
As per zero-product reverse property, we have $(6x
+5)(3x-1)=0$
Now, apply FOIL METHOD
$(6x+5)(3x-1)=0 \implies 18x^2-6x+15x-5=0$
or, $18x^2+9x-5=0$
