Chapter 8 - Section 8.2 - The Quadratic Formula - Exercise Set - Page 608: 40

$x=${$-6,-1$}

Given: $(2x+7)^2=25$ Need to apply square root property. $(2x+7)^2=25$ This implies that $2x+7=\pm \sqrt {25}$ or, $2x+7=\pm 5$ or, $x=\dfrac{-7- 5}{2},\dfrac{-7 + 5}{2}$ Hence, our solution set is: $x=${$-6,-1$}