Answer
$x=${$\dfrac{2- \sqrt {10}}{3},\dfrac{2+ \sqrt {10}}{3}$}
Work Step by Step
Given: $(3x-2)^2=10$
Need to apply square root property.
$(3x-2)^2=10$
This implies that $3x-2=\pm \sqrt {10}$
or, $3x=2\pm \sqrt {10}$
or, $x=\dfrac{2- \sqrt {10}}{3},\dfrac{2+ \sqrt {10}}{3}$
Hence, our solution set is:
$x=${$\dfrac{2- \sqrt {10}}{3},\dfrac{2+ \sqrt {10}}{3}$}
